What are the solutions to the equation 9a^2-18a+5=0 ?

The solutions to the equation 9a^2-18a+5=0 are a= 5/3 ,a= 1/3

Find the zeros of 9a^2-18a+5=0

The zeros of 9a^2-18a+5=0 are a= 5/3 ,a= 1/3

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9 a^{2} - 18 a + 5 = 0

a = \frac{5}{3}, a = \frac{1}{3}

Decimal Notation

a = 1.66666 \dots, a = 0.33333 \dots

Solution steps

9 a^{2} - 18 a + 5 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 9 \cdot 5}{2 \cdot 9}

(- 18)^{2} - 4 \cdot 9 \cdot 5 = 12

a_{1, 2} = \frac{- ( - 18 ) \pm 12}{2 \cdot 9}

Separate the solutions

a_{1} = \frac{- ( - 18 ) + 12}{2 \cdot 9}, a_{2} = \frac{- ( - 18 ) - 12}{2 \cdot 9}

a = \frac{- ( - 18 ) + 12}{2 \cdot 9} : \frac{5}{3}

a = \frac{- ( - 18 ) - 12}{2 \cdot 9} : \frac{1}{3}

The solutions to the quadratic equation are:

a = \frac{5}{3}, a = \frac{1}{3}

8 x^{2} + 20 x = 0

4 x^{2} + 4 x + 1 = 81

3 (5 x - 3)^{2} - 24 = - 21

y, x^{2} - 18 x y + y^{2} = 18

x^{2} - 6 x + c

What are the solutions to the equation 9a^2-18a+5=0 ?
The solutions to the equation 9a^2-18a+5=0 are a= 5/3 ,a= 1/3
Find the zeros of 9a^2-18a+5=0
The zeros of 9a^2-18a+5=0 are a= 5/3 ,a= 1/3