What are the solutions to the equation roots x^2-6x+c ?

The solutions to the equation roots x^2-6x+c are x=3+sqrt(-c+9),x=3-sqrt(-c+9)

Find the zeros of roots x^2-6x+c

The zeros of roots x^2-6x+c are x=3+sqrt(-c+9),x=3-sqrt(-c+9)

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roots

x^{2} - 6 x + c

x = 3 + - c + 9, x = 3 - - c + 9

Solution steps

x^{2} - 6 x + c

The roots are the intercepts with the x-axis

(y = 0)

x^{2} - 6 x + c = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot c}{2 \cdot 1}

Simplify

(- 6)^{2} - 4 \cdot 1 \cdot c : 2 9 - c

x_{1, 2} = \frac{- ( - 6 ) \pm 2 9 - c}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 9 - c}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 2 9 - c}{2 \cdot 1}

x = \frac{- ( - 6 ) + 2 9 - c}{2 \cdot 1} : 3 + - c + 9

x = \frac{- ( - 6 ) - 2 9 - c}{2 \cdot 1} : 3 - - c + 9

The solutions to the quadratic equation are:

x = 3 + - c + 9, x = 3 - - c + 9

2 d^{2} + 4 = 5 d

7 x^{2} - 5 x + 3 = 0

3 x^{2} + 15 = 6 x

6 x^{2} + 3 (- x + 2)^{2} - 12 = 0

x^{2} - 2 = 2 x^{2} + x - 4

What are the solutions to the equation roots x^2-6x+c ?
The solutions to the equation roots x^2-6x+c are x=3+sqrt(-c+9),x=3-sqrt(-c+9)
Find the zeros of roots x^2-6x+c
The zeros of roots x^2-6x+c are x=3+sqrt(-c+9),x=3-sqrt(-c+9)