What are the solutions to the equation 6x^2+3(-x+2)^2-12=0 ?

The solutions to the equation 6x^2+3(-x+2)^2-12=0 are x= 4/3 ,x=0

Find the zeros of 6x^2+3(-x+2)^2-12=0

The zeros of 6x^2+3(-x+2)^2-12=0 are x= 4/3 ,x=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

6 x^{2} + 3 (- x + 2)^{2} - 12 = 0

x = \frac{4}{3}, x = 0

Decimal Notation

x = 1.33333 \dots, x = 0

Solution steps

6 x^{2} + 3 (- x + 2)^{2} - 12 = 0

Expand

6 x^{2} + 3 (- x + 2)^{2} - 12 : 9 x^{2} - 12 x

9 x^{2} - 12 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 9 \cdot 0}{2 \cdot 9}

(- 12)^{2} - 4 \cdot 9 \cdot 0 = 12

x_{1, 2} = \frac{- ( - 12 ) \pm 12}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 12}{2 \cdot 9}, x_{2} = \frac{- ( - 12 ) - 12}{2 \cdot 9}

x = \frac{- ( - 12 ) + 12}{2 \cdot 9} : \frac{4}{3}

x = \frac{- ( - 12 ) - 12}{2 \cdot 9} : 0

The solutions to the quadratic equation are:

x = \frac{4}{3}, x = 0

x^{2} - 2 = 2 x^{2} + x - 4

4 x^{2} + 85 = - 36 x

4 k^{2} + 6 k + 1 = 2 k

3 v^{2} + 10 v + 1 = v

y, x^{2} - x y + y^{2} = 0

What are the solutions to the equation 6x^2+3(-x+2)^2-12=0 ?
The solutions to the equation 6x^2+3(-x+2)^2-12=0 are x= 4/3 ,x=0
Find the zeros of 6x^2+3(-x+2)^2-12=0
The zeros of 6x^2+3(-x+2)^2-12=0 are x= 4/3 ,x=0