What are the solutions to the equation 4k^2+6k+1=2k ?

The solutions to the equation 4k^2+6k+1=2k are k=-1/2

Find the zeros of 4k^2+6k+1=2k

The zeros of 4k^2+6k+1=2k are k=-1/2

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4 k^{2} + 6 k + 1 = 2 k

k = - \frac{1}{2}

Decimal Notation

k = - 0.5

Solution steps

4 k^{2} + 6 k + 1 = 2 k

Move

2 k

to the left side

4 k^{2} + 4 k + 1 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 4 \cdot 1}{2 \cdot 4}

4^{2} - 4 \cdot 4 \cdot 1 = 0

k_{1, 2} = \frac{- 4 \pm 0}{2 \cdot 4}

k = \frac{- 4}{2 \cdot 4}

\frac{- 4}{2 \cdot 4} = - \frac{1}{2}

k = - \frac{1}{2}

The solution to the quadratic equation is:

k = - \frac{1}{2}

3 v^{2} + 10 v + 1 = v

y, x^{2} - x y + y^{2} = 0

y, 3 x^{2} + 2 x y + y^{2} = 2

x, c x^{2} + x + y^{2} = 0

4 x^{2} + 85 = - 36 x

What are the solutions to the equation 4k^2+6k+1=2k ?
The solutions to the equation 4k^2+6k+1=2k are k=-1/2
Find the zeros of 4k^2+6k+1=2k
The zeros of 4k^2+6k+1=2k are k=-1/2