What are the solutions to the equation r^2-6r+12=0 ?

The solutions to the equation r^2-6r+12=0 are r=3+sqrt(3)i,r=3-sqrt(3)i

Find the zeros of r^2-6r+12=0

The zeros of r^2-6r+12=0 are r=3+sqrt(3)i,r=3-sqrt(3)i

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r^{2} - 6 r + 12 = 0

r = 3 + 3 i, r = 3 - 3 i

Solution steps

r^{2} - 6 r + 12 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 12}{2 \cdot 1}

Simplify

(- 6)^{2} - 4 \cdot 1 \cdot 12 : 23 i

r_{1, 2} = \frac{- ( - 6 ) \pm 2 3 i}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- ( - 6 ) + 2 3 i}{2 \cdot 1}, r_{2} = \frac{- ( - 6 ) - 2 3 i}{2 \cdot 1}

r = \frac{- ( - 6 ) + 2 3 i}{2 \cdot 1} : 3 + 3 i

r = \frac{- ( - 6 ) - 2 3 i}{2 \cdot 1} : 3 - 3 i

The solutions to the quadratic equation are:

r = 3 + 3 i, r = 3 - 3 i

(1 - k) x^{2} + x + k = 0

81 = \frac{n}{2} (1.5 + n)

2 x^{2} - 19 x - 10 = 0

2 x^{2} + x - 3

x^{2} - 4 x = 77

What are the solutions to the equation r^2-6r+12=0 ?
The solutions to the equation r^2-6r+12=0 are r=3+sqrt(3)i,r=3-sqrt(3)i
Find the zeros of r^2-6r+12=0
The zeros of r^2-6r+12=0 are r=3+sqrt(3)i,r=3-sqrt(3)i