What are the solutions to the equation roots x^2-4x-4 ?

The solutions to the equation roots x^2-4x-4 are x=2(1+sqrt(2)),x=2(1-sqrt(2))

Find the zeros of roots x^2-4x-4

The zeros of roots x^2-4x-4 are x=2(1+sqrt(2)),x=2(1-sqrt(2))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

roots

x^{2} - 4 x - 4

x = 2 (1 + 2), x = 2 (1 - 2)

Solution steps

x^{2} - 4 x - 4

The roots are the intercepts with the x-axis

(y = 0)

x^{2} - 4 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 4 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 4) = 42

x_{1, 2} = \frac{- ( - 4 ) \pm 4 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 4 2}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 4 2}{2 \cdot 1}

x = \frac{- ( - 4 ) + 4 2}{2 \cdot 1} : 2 (1 + 2)

x = \frac{- ( - 4 ) - 4 2}{2 \cdot 1} : 2 (1 - 2)

The solutions to the quadratic equation are:

x = 2 (1 + 2), x = 2 (1 - 2)

x^{2} - 3 x = 10

9 x^{2} + 2 x - 3 = 0

3 t^{2} - 82 t + 27 = 0

9 x^{2} + 30 x = - 25

4 x^{2} - \frac{9}{49} = 0

What are the solutions to the equation roots x^2-4x-4 ?
The solutions to the equation roots x^2-4x-4 are x=2(1+sqrt(2)),x=2(1-sqrt(2))
Find the zeros of roots x^2-4x-4
The zeros of roots x^2-4x-4 are x=2(1+sqrt(2)),x=2(1-sqrt(2))