What are the solutions to the equation -5x^2-20x+105=0 ?

The solutions to the equation -5x^2-20x+105=0 are x=-7,x=3

Find the zeros of -5x^2-20x+105=0

The zeros of -5x^2-20x+105=0 are x=-7,x=3

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- 5 x^{2} - 20 x + 105 = 0

x = - 7, x = 3

Solution steps

- 5 x^{2} - 20 x + 105 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 ( - 5 ) \cdot 105}{2 ( - 5 )}

(- 20)^{2} - 4 (- 5) \cdot 105 = 50

x_{1, 2} = \frac{- ( - 20 ) \pm 50}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 50}{2 ( - 5 )}, x_{2} = \frac{- ( - 20 ) - 50}{2 ( - 5 )}

x = \frac{- ( - 20 ) + 50}{2 ( - 5 )} : - 7

x = \frac{- ( - 20 ) - 50}{2 ( - 5 )} : 3

The solutions to the quadratic equation are:

x = - 7, x = 3

2 x^{2} + 24 = 16 x

(x + 5)^{2} - 4 = - 28

4 x^{2} + 45 = - 28 x

x^{2} + 6 x + 9 = \frac{6 x}{0.42}

r^{2} - r + \frac{1}{4} = 0

What are the solutions to the equation -5x^2-20x+105=0 ?
The solutions to the equation -5x^2-20x+105=0 are x=-7,x=3
Find the zeros of -5x^2-20x+105=0
The zeros of -5x^2-20x+105=0 are x=-7,x=3