What is the answer to 17(2)+44=12+3k+4-k ?

The answer to 17(2)+44=12+3k+4-k is k=31

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17(2)+44=12+3k+4-k

17 (2) + 44 = 12 + 3 k + 4 - k

k = 31

Solution steps

17 (2) + 44 = 12 + 3 k + 4 - k

Switch sides

12 + 3 k + 4 - k = 17 (2) + 44

Group like terms

3 k - k + 12 + 4 = 17 (2) + 44

Add similar elements:

3 k - k = 2 k

2 k + 12 + 4 = 17 (2) + 44

Add the numbers:

12 + 4 = 16

2 k + 16 = 17 (2) + 44

Remove parentheses:

(a) = a

2 k + 16 = 17 \cdot 2 + 44

Multiply the numbers:

17 \cdot 2 = 34

2 k + 16 = 34 + 44

Add the numbers:

34 + 44 = 78

2 k + 16 = 78

Move

16

to the right side

2 k = 62

Divide both sides by

2

k = 31

\frac{w}{8} < - 4

x + \frac{2}{5} > \frac{2}{3} - 2 x

k^{2} + 4 k + 4 = 0

4 x^{2} + x - 33

\frac{4 - 2}{2}

What is the answer to 17(2)+44=12+3k+4-k ?
The answer to 17(2)+44=12+3k+4-k is k=31
Solve for k: 17(2)+44=12+3k+4-k
The solution is k=31