What are the solutions to the equation -(x+2)^2=54 ?

The solutions to the equation -(x+2)^2=54 are x=3sqrt(6)i-2,x=-3sqrt(6)i-2

Find the zeros of -(x+2)^2=54

The zeros of -(x+2)^2=54 are x=3sqrt(6)i-2,x=-3sqrt(6)i-2

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- (x + 2)^{2} = 54

x = 36 i - 2, x = - 36 i - 2

Solution steps

- (x + 2)^{2} = 54

Divide both sides by

- 1

(x + 2)^{2} = - 54

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 2 = - 54 : x = 36 i - 2

Solve

x + 2 = - - 54 : x = - 36 i - 2

The solutions to the quadratic equation are:

x = 36 i - 2, x = - 36 i - 2

x^{2} + 12 x + 36 = - 81

x^{2} - 6 x - 27 = 0

3 x^{2} + 10 x - 8 = 0

6 x^{2} - 72 x + 192 = 0

16 x - 8 = 9 x^{2} - 9 x - 108

What are the solutions to the equation -(x+2)^2=54 ?
The solutions to the equation -(x+2)^2=54 are x=3sqrt(6)i-2,x=-3sqrt(6)i-2
Find the zeros of -(x+2)^2=54
The zeros of -(x+2)^2=54 are x=3sqrt(6)i-2,x=-3sqrt(6)i-2