What are the solutions to the equation 3(x^2-7)-4=-7 ?

The solutions to the equation 3(x^2-7)-4=-7 are x=sqrt(6),x=-sqrt(6)

Find the zeros of 3(x^2-7)-4=-7

The zeros of 3(x^2-7)-4=-7 are x=sqrt(6),x=-sqrt(6)

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3 (x^{2} - 7) - 4 = - 7

x = 6, x = - 6

Decimal Notation

x = 2.44948 \dots, x = - 2.44948 \dots

Solution steps

3 (x^{2} - 7) - 4 = - 7

Move

4

to the right side

3 (x^{2} - 7) = - 3

Divide both sides by

3

x^{2} - 7 = - 1

Move

7

to the right side

x^{2} = 6

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 6, x = - 6

x^{2} - 31 = 2 x

2 x^{2} + 6 x - 7 = 2

x, 3 x^{2} + 30 x - 5 = 0

5 r^{2} + 24 r - 3 = 2

m, x^{2} + m (x)^{2} x (m (x) - 2) = 2 m (x)^{5}

What are the solutions to the equation 3(x^2-7)-4=-7 ?
The solutions to the equation 3(x^2-7)-4=-7 are x=sqrt(6),x=-sqrt(6)
Find the zeros of 3(x^2-7)-4=-7
The zeros of 3(x^2-7)-4=-7 are x=sqrt(6),x=-sqrt(6)