What are the solutions to the equation -x^2-8x=20 ?

The solutions to the equation -x^2-8x=20 are x=-4-2i,x=-4+2i

Find the zeros of -x^2-8x=20

The zeros of -x^2-8x=20 are x=-4-2i,x=-4+2i

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- x^{2} - 8 x = 20

x = - 4 - 2 i, x = - 4 + 2 i

Solution steps

- x^{2} - 8 x = 20

Move

20

to the left side

- x^{2} - 8 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 ( - 1 ) ( - 20 )}{2 ( - 1 )}

Simplify

(- 8)^{2} - 4 (- 1) (- 20) : 4 i

x_{1, 2} = \frac{- ( - 8 ) \pm 4 i}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 4 i}{2 ( - 1 )}, x_{2} = \frac{- ( - 8 ) - 4 i}{2 ( - 1 )}

x = \frac{- ( - 8 ) + 4 i}{2 ( - 1 )} : - 4 - 2 i

x = \frac{- ( - 8 ) - 4 i}{2 ( - 1 )} : - 4 + 2 i

The solutions to the quadratic equation are:

x = - 4 - 2 i, x = - 4 + 2 i

- x^{2} - 3.5 = - 12.5

11 x^{2} - 22 x = - 11

- 16 t^{2} + 256 = 0

3 x^{2} - 5 = - 5 x - 3

16 x^{2} + 11 = - 24 x

What are the solutions to the equation -x^2-8x=20 ?
The solutions to the equation -x^2-8x=20 are x=-4-2i,x=-4+2i
Find the zeros of -x^2-8x=20
The zeros of -x^2-8x=20 are x=-4-2i,x=-4+2i