What are the solutions to the equation -16t^2+256=0 ?

The solutions to the equation -16t^2+256=0 are t=4,t=-4

Find the zeros of -16t^2+256=0

The zeros of -16t^2+256=0 are t=4,t=-4

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- 16 t^{2} + 256 = 0

t = 4, t = - 4

Solution steps

- 16 t^{2} + 256 = 0

Move

256

to the right side

- 16 t^{2} = - 256

Divide both sides by

- 16

t^{2} = 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

t = 16, t = - 16

16 = 4

- 16 = - 4

t = 4, t = - 4

3 x^{2} - 5 = - 5 x - 3

16 x^{2} + 11 = - 24 x

0 = x^{2} + 6 x + 9

4 x^{2} + 4 = 5

- 3 x^{2} = 4

What are the solutions to the equation -16t^2+256=0 ?
The solutions to the equation -16t^2+256=0 are t=4,t=-4
Find the zeros of -16t^2+256=0
The zeros of -16t^2+256=0 are t=4,t=-4