What are the solutions to the equation 4(x+7)^2=13 ?

The solutions to the equation 4(x+7)^2=13 are x=(sqrt(13))/2-7,x=-(sqrt(13))/2-7

Find the zeros of 4(x+7)^2=13

The zeros of 4(x+7)^2=13 are x=(sqrt(13))/2-7,x=-(sqrt(13))/2-7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 (x + 7)^{2} = 13

x = \frac{13}{2} - 7, x = - \frac{13}{2} - 7

Decimal Notation

x = - 5.19722 \dots, x = - 8.80277 \dots

Solution steps

4 (x + 7)^{2} = 13

Divide both sides by

4

(x + 7)^{2} = \frac{13}{4}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 7 = \frac{13}{4} : x = \frac{13}{2} - 7

Solve

x + 7 = - \frac{13}{4} : x = - \frac{13}{2} - 7

The solutions to the quadratic equation are:

x = \frac{13}{2} - 7, x = - \frac{13}{2} - 7

- 4.905 t^{2} + 12 t + 80 = 0

4 x^{2} - 100 = 0

3 4^{2} + 1 6^{2} = c^{2}

5 x^{2} - 30 x = - 4 x - 5

y, y^{2} = \frac{1}{9} x^{2}

What are the solutions to the equation 4(x+7)^2=13 ?
The solutions to the equation 4(x+7)^2=13 are x=(sqrt(13))/2-7,x=-(sqrt(13))/2-7
Find the zeros of 4(x+7)^2=13
The zeros of 4(x+7)^2=13 are x=(sqrt(13))/2-7,x=-(sqrt(13))/2-7