What are the solutions to the equation 34^2+16^2=c^2 ?

The solutions to the equation 34^2+16^2=c^2 are c=2sqrt(353),c=-2sqrt(353)

Find the zeros of 34^2+16^2=c^2

The zeros of 34^2+16^2=c^2 are c=2sqrt(353),c=-2sqrt(353)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 4^{2} + 1 6^{2} = c^{2}

c = 2353, c = - 2353

Decimal Notation

c = 37.57658 \dots, c = - 37.57658 \dots

Solution steps

3 4^{2} + 1 6^{2} = c^{2}

Switch sides

c^{2} = 3 4^{2} + 1 6^{2}

Simplify

3 4^{2} + 1 6^{2} : 1412

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 1412, c = - 1412

1412 = 2353

- 1412 = - 2353

c = 2353, c = - 2353

5 x^{2} - 30 x = - 4 x - 5

y, y^{2} = \frac{1}{9} x^{2}

- p^{2} - 3 p - 13 = - 2 p^{2}

7 x^{2} + 12 x + 5 = 0

2.5 x^{2} + x + 1 = 0

What are the solutions to the equation 34^2+16^2=c^2 ?
The solutions to the equation 34^2+16^2=c^2 are c=2sqrt(353),c=-2sqrt(353)
Find the zeros of 34^2+16^2=c^2
The zeros of 34^2+16^2=c^2 are c=2sqrt(353),c=-2sqrt(353)