What are the solutions to the equation 2.5x^2+x+1=0 ?

The solutions to the equation 2.5x^2+x+1=0 are x=-1/5+i 3/5 ,x=-1/5-i 3/5

Find the zeros of 2.5x^2+x+1=0

The zeros of 2.5x^2+x+1=0 are x=-1/5+i 3/5 ,x=-1/5-i 3/5

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2.5 x^{2} + x + 1 = 0

x = - \frac{1}{5} + i \frac{3}{5}, x = - \frac{1}{5} - i \frac{3}{5}

Solution steps

2.5 x^{2} + x + 1 = 0

Multiply both sides by

10

25 x^{2} + 10 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 25 \cdot 10}{2 \cdot 25}

Simplify

1 0^{2} - 4 \cdot 25 \cdot 10 : 30 i

x_{1, 2} = \frac{- 10 \pm 30 i}{2 \cdot 25}

Separate the solutions

x_{1} = \frac{- 10 + 30 i}{2 \cdot 25}, x_{2} = \frac{- 10 - 30 i}{2 \cdot 25}

x = \frac{- 10 + 30 i}{2 \cdot 25} : - \frac{1}{5} + i \frac{3}{5}

x = \frac{- 10 - 30 i}{2 \cdot 25} : - \frac{1}{5} - i \frac{3}{5}

The solutions to the quadratic equation are:

x = - \frac{1}{5} + i \frac{3}{5}, x = - \frac{1}{5} - i \frac{3}{5}

4 s^{2} - 11 s - 3 = 0

3 x^{2} + 15 x = - 22

30 + 27 x = 400 - x^{2}

y, 4 x^{2} + 5 x y + y^{2} + 3 x - 2 y - 7 = 0

x, t (x) = - 2 x + \frac{1}{3} x^{2}

What are the solutions to the equation 2.5x^2+x+1=0 ?
The solutions to the equation 2.5x^2+x+1=0 are x=-1/5+i 3/5 ,x=-1/5-i 3/5
Find the zeros of 2.5x^2+x+1=0
The zeros of 2.5x^2+x+1=0 are x=-1/5+i 3/5 ,x=-1/5-i 3/5