What are the solutions to the equation 3x^2+15x=-22 ?

The solutions to the equation 3x^2+15x=-22 are x=-5/2+i(sqrt(39))/6 ,x=-5/2-i(sqrt(39))/6

Find the zeros of 3x^2+15x=-22

The zeros of 3x^2+15x=-22 are x=-5/2+i(sqrt(39))/6 ,x=-5/2-i(sqrt(39))/6

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3 x^{2} + 15 x = - 22

x = - \frac{5}{2} + i \frac{39}{6}, x = - \frac{5}{2} - i \frac{39}{6}

Solution steps

3 x^{2} + 15 x = - 22

Move

22

to the left side

3 x^{2} + 15 x + 22 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 \cdot 3 \cdot 22}{2 \cdot 3}

Simplify

1 5^{2} - 4 \cdot 3 \cdot 22 : 39 i

x_{1, 2} = \frac{- 15 \pm 39 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 15 + 39 i}{2 \cdot 3}, x_{2} = \frac{- 15 - 39 i}{2 \cdot 3}

x = \frac{- 15 + 39 i}{2 \cdot 3} : - \frac{5}{2} + i \frac{39}{6}

x = \frac{- 15 - 39 i}{2 \cdot 3} : - \frac{5}{2} - i \frac{39}{6}

The solutions to the quadratic equation are:

x = - \frac{5}{2} + i \frac{39}{6}, x = - \frac{5}{2} - i \frac{39}{6}

30 + 27 x = 400 - x^{2}

y, 4 x^{2} + 5 x y + y^{2} + 3 x - 2 y - 7 = 0

x, t (x) = - 2 x + \frac{1}{3} x^{2}

x^{2} + 3

(2 x - 1)^{2} = 75

What are the solutions to the equation 3x^2+15x=-22 ?
The solutions to the equation 3x^2+15x=-22 are x=-5/2+i(sqrt(39))/6 ,x=-5/2-i(sqrt(39))/6
Find the zeros of 3x^2+15x=-22
The zeros of 3x^2+15x=-22 are x=-5/2+i(sqrt(39))/6 ,x=-5/2-i(sqrt(39))/6