What are the solutions to the equation 10x^2-2x+13=3 ?

The solutions to the equation 10x^2-2x+13=3 are x= 1/10+i(3sqrt(11))/(10),x= 1/10-i(3sqrt(11))/(10)

Find the zeros of 10x^2-2x+13=3

The zeros of 10x^2-2x+13=3 are x= 1/10+i(3sqrt(11))/(10),x= 1/10-i(3sqrt(11))/(10)

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10 x^{2} - 2 x + 13 = 3

x = \frac{1}{10} + i \frac{3 11}{10}, x = \frac{1}{10} - i \frac{3 11}{10}

Solution steps

10 x^{2} - 2 x + 13 = 3

Move

3

to the left side

10 x^{2} - 2 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 10 \cdot 10}{2 \cdot 10}

Simplify

(- 2)^{2} - 4 \cdot 10 \cdot 10 : 611 i

x_{1, 2} = \frac{- ( - 2 ) \pm 6 11 i}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 6 11 i}{2 \cdot 10}, x_{2} = \frac{- ( - 2 ) - 6 11 i}{2 \cdot 10}

x = \frac{- ( - 2 ) + 6 11 i}{2 \cdot 10} : \frac{1}{10} + i \frac{3 11}{10}

x = \frac{- ( - 2 ) - 6 11 i}{2 \cdot 10} : \frac{1}{10} - i \frac{3 11}{10}

The solutions to the quadratic equation are:

x = \frac{1}{10} + i \frac{3 11}{10}, x = \frac{1}{10} - i \frac{3 11}{10}

12 x^{2} - 36 x - 48 = 0

(9 x - 15)^{2} - 2 (9 x - 15) + 1 = 0

x^{2} + x - 12 = 0

3 x^{2} + 5 x - 100 = 0

y, y^{2} + y - x^{2} - x = 0

What are the solutions to the equation 10x^2-2x+13=3 ?
The solutions to the equation 10x^2-2x+13=3 are x= 1/10+i(3sqrt(11))/(10),x= 1/10-i(3sqrt(11))/(10)
Find the zeros of 10x^2-2x+13=3
The zeros of 10x^2-2x+13=3 are x= 1/10+i(3sqrt(11))/(10),x= 1/10-i(3sqrt(11))/(10)