What are the solutions to the equation solvefor y,y^2+y-x^2-x=0 ?

The solutions to the equation solvefor y,y^2+y-x^2-x=0 are y=x,y=-x-1

Find the zeros of solvefor y,y^2+y-x^2-x=0

The zeros of solvefor y,y^2+y-x^2-x=0 are y=x,y=-x-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solve for

y, y^{2} + y - x^{2} - x = 0

y = x, y = - x - 1

Solution steps

y^{2} + y - x^{2} - x = 0

Factor

y^{2} + y - x^{2} - x : (y - x) (y + x + 1)

(y - x) (y + x + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

y - x = 0 or y + x + 1 = 0

Solve

y - x = 0 : y = x

Solve

y + x + 1 = 0 : y = - x - 1

The solutions to the quadratic equation are:

y = x, y = - x - 1

(3 x + 8)^{2} + 21 = 47

x^{2} - 20 = - 8 x

x^{2} = 16 x + 8

(2 x - 5) (x + 1) + 12 x = 0

x^{2} - 14 x + 9 = - 60

What are the solutions to the equation solvefor y,y^2+y-x^2-x=0 ?
The solutions to the equation solvefor y,y^2+y-x^2-x=0 are y=x,y=-x-1
Find the zeros of solvefor y,y^2+y-x^2-x=0
The zeros of solvefor y,y^2+y-x^2-x=0 are y=x,y=-x-1