What are the solutions to the equation (3x+8)^2+21=47 ?

The solutions to the equation (3x+8)^2+21=47 are x=(sqrt(26)-8)/3 ,x=(-sqrt(26)-8)/3

Find the zeros of (3x+8)^2+21=47

The zeros of (3x+8)^2+21=47 are x=(sqrt(26)-8)/3 ,x=(-sqrt(26)-8)/3

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(3 x + 8)^{2} + 21 = 47

x = \frac{26 - 8}{3}, x = \frac{- 26 - 8}{3}

Decimal Notation

x = - 0.96699 \dots, x = - 4.36633 \dots

Solution steps

(3 x + 8)^{2} + 21 = 47

Move

21

to the right side

(3 x + 8)^{2} = 26

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x + 8 = 26 : x = \frac{26 - 8}{3}

Solve

3 x + 8 = - 26 : x = \frac{- 26 - 8}{3}

The solutions to the quadratic equation are:

x = \frac{26 - 8}{3}, x = \frac{- 26 - 8}{3}

x^{2} - 20 = - 8 x

x^{2} = 16 x + 8

(2 x - 5) (x + 1) + 12 x = 0

x^{2} - 14 x + 9 = - 60

2 (x - 3) = x (13 - x)

What are the solutions to the equation (3x+8)^2+21=47 ?
The solutions to the equation (3x+8)^2+21=47 are x=(sqrt(26)-8)/3 ,x=(-sqrt(26)-8)/3
Find the zeros of (3x+8)^2+21=47
The zeros of (3x+8)^2+21=47 are x=(sqrt(26)-8)/3 ,x=(-sqrt(26)-8)/3