What are the solutions to the equation 2x-x(x+3)+5=20 ?

The solutions to the equation 2x-x(x+3)+5=20 are x=-1/2-i(sqrt(59))/2 ,x=-1/2+i(sqrt(59))/2

Find the zeros of 2x-x(x+3)+5=20

The zeros of 2x-x(x+3)+5=20 are x=-1/2-i(sqrt(59))/2 ,x=-1/2+i(sqrt(59))/2

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2 x - x (x + 3) + 5 = 20

x = - \frac{1}{2} - i \frac{59}{2}, x = - \frac{1}{2} + i \frac{59}{2}

Solution steps

2 x - x (x + 3) + 5 = 20

Expand

2 x - x (x + 3) + 5 : - x^{2} - x + 5

- x^{2} - x + 5 = 20

Move

20

to the left side

- x^{2} - x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 ( - 1 ) ( - 15 )}{2 ( - 1 )}

Simplify

(- 1)^{2} - 4 (- 1) (- 15) : 59 i

x_{1, 2} = \frac{- ( - 1 ) \pm 59 i}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 59 i}{2 ( - 1 )}, x_{2} = \frac{- ( - 1 ) - 59 i}{2 ( - 1 )}

x = \frac{- ( - 1 ) + 59 i}{2 ( - 1 )} : - \frac{1}{2} - i \frac{59}{2}

x = \frac{- ( - 1 ) - 59 i}{2 ( - 1 )} : - \frac{1}{2} + i \frac{59}{2}

The solutions to the quadratic equation are:

x = - \frac{1}{2} - i \frac{59}{2}, x = - \frac{1}{2} + i \frac{59}{2}

x^{2} = - 2 x + 24

7 x^{2} - 47 = 128

\frac{1}{4} x^{2} - 4 = 0

4 m^{2} - 5 m - 3 = 2 m

x^{2} - 9 x + 3 = 3

What are the solutions to the equation 2x-x(x+3)+5=20 ?
The solutions to the equation 2x-x(x+3)+5=20 are x=-1/2-i(sqrt(59))/2 ,x=-1/2+i(sqrt(59))/2
Find the zeros of 2x-x(x+3)+5=20
The zeros of 2x-x(x+3)+5=20 are x=-1/2-i(sqrt(59))/2 ,x=-1/2+i(sqrt(59))/2