What are the solutions to the equation -4x^2-24x+64=0 ?

The solutions to the equation -4x^2-24x+64=0 are x=-8,x=2

Find the zeros of -4x^2-24x+64=0

The zeros of -4x^2-24x+64=0 are x=-8,x=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 4 x^{2} - 24 x + 64 = 0

x = - 8, x = 2

Solution steps

- 4 x^{2} - 24 x + 64 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 ( - 4 ) \cdot 64}{2 ( - 4 )}

(- 24)^{2} - 4 (- 4) \cdot 64 = 40

x_{1, 2} = \frac{- ( - 24 ) \pm 40}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- ( - 24 ) + 40}{2 ( - 4 )}, x_{2} = \frac{- ( - 24 ) - 40}{2 ( - 4 )}

x = \frac{- ( - 24 ) + 40}{2 ( - 4 )} : - 8

x = \frac{- ( - 24 ) - 40}{2 ( - 4 )} : 2

The solutions to the quadratic equation are:

x = - 8, x = 2

4 x^{2} + x + 1

2 m^{2} + 18 = 15 m

0 x^{3} - x^{2} + 2 x + 4 = 0

12 v^{2} - 9 v - 25 = - 4 v

n^{2} + 225 n - 2835000 = 0

What are the solutions to the equation -4x^2-24x+64=0 ?
The solutions to the equation -4x^2-24x+64=0 are x=-8,x=2
Find the zeros of -4x^2-24x+64=0
The zeros of -4x^2-24x+64=0 are x=-8,x=2