What are the solutions to the equation 3n^2+17n+17=-2 ?

The solutions to the equation 3n^2+17n+17=-2 are n=(-17+sqrt(61))/6 ,n=(-17-sqrt(61))/6

Find the zeros of 3n^2+17n+17=-2

The zeros of 3n^2+17n+17=-2 are n=(-17+sqrt(61))/6 ,n=(-17-sqrt(61))/6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 n^{2} + 17 n + 17 = - 2

n = \frac{- 17 + 61}{6}, n = \frac{- 17 - 61}{6}

Decimal Notation

n = - 1.53162 \dots, n = - 4.13504 \dots

Solution steps

3 n^{2} + 17 n + 17 = - 2

Move

2

to the left side

3 n^{2} + 17 n + 19 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 \cdot 3 \cdot 19}{2 \cdot 3}

1 7^{2} - 4 \cdot 3 \cdot 19 = 61

n_{1, 2} = \frac{- 17 \pm 61}{2 \cdot 3}

Separate the solutions

n_{1} = \frac{- 17 + 61}{2 \cdot 3}, n_{2} = \frac{- 17 - 61}{2 \cdot 3}

n = \frac{- 17 + 61}{2 \cdot 3} : \frac{- 17 + 61}{6}

n = \frac{- 17 - 61}{2 \cdot 3} : \frac{- 17 - 61}{6}

The solutions to the quadratic equation are:

n = \frac{- 17 + 61}{6}, n = \frac{- 17 - 61}{6}

0 = 3 t^{2} - 18 t + 24

2 x^{2} - 18 = 3 x - 13

2 b^{2} - 4 b - 6 = 0

(2 x + 1)^{2} = x (3 x + 2)

8 x^{2} + 16 x = 42

What are the solutions to the equation 3n^2+17n+17=-2 ?
The solutions to the equation 3n^2+17n+17=-2 are n=(-17+sqrt(61))/6 ,n=(-17-sqrt(61))/6
Find the zeros of 3n^2+17n+17=-2
The zeros of 3n^2+17n+17=-2 are n=(-17+sqrt(61))/6 ,n=(-17-sqrt(61))/6