What are the solutions to the equation (x+2)^2-3=4x ?

The solutions to the equation (x+2)^2-3=4x are x=i,x=-i

Find the zeros of (x+2)^2-3=4x

The zeros of (x+2)^2-3=4x are x=i,x=-i

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(x + 2)^{2} - 3 = 4 x

x = i, x = - i

Solution steps

(x + 2)^{2} - 3 = 4 x

Expand

(x + 2)^{2} - 3 : x^{2} + 4 x + 1

x^{2} + 4 x + 1 = 4 x

Move

1

to the right side

x^{2} + 4 x = 4 x - 1

Move

4 x

to the left side

x^{2} = - 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 1, x = - - 1

- 1 = i

- - 1 = - i

x = i, x = - i

y, x^{2} y^{2} - 2 x = 3

4 x^{2} + 2 x + 7

x^{2} - 4 x - 5 = 16

x^{2} - 2 x - 8

x^{2} - 2 x

What are the solutions to the equation (x+2)^2-3=4x ?
The solutions to the equation (x+2)^2-3=4x are x=i,x=-i
Find the zeros of (x+2)^2-3=4x
The zeros of (x+2)^2-3=4x are x=i,x=-i