What are the solutions to the equation x^2-4x-5=16 ?

The solutions to the equation x^2-4x-5=16 are x=7,x=-3

Find the zeros of x^2-4x-5=16

The zeros of x^2-4x-5=16 are x=7,x=-3

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x^{2} - 4 x - 5 = 16

x = 7, x = - 3

Solution steps

x^{2} - 4 x - 5 = 16

Move

16

to the left side

x^{2} - 4 x - 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 21 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 21) = 10

x_{1, 2} = \frac{- ( - 4 ) \pm 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 10}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 10}{2 \cdot 1}

x = \frac{- ( - 4 ) + 10}{2 \cdot 1} : 7

x = \frac{- ( - 4 ) - 10}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = 7, x = - 3

x^{2} - 2 x - 8

x^{2} - 2 x

s^{2} + 8 s + 25

s^{2} - 4 s + 8

4 x^{2} = - 64

What are the solutions to the equation x^2-4x-5=16 ?
The solutions to the equation x^2-4x-5=16 are x=7,x=-3
Find the zeros of x^2-4x-5=16
The zeros of x^2-4x-5=16 are x=7,x=-3