What are the solutions to the equation 4d^2+17d+10=-d^2 ?

The solutions to the equation 4d^2+17d+10=-d^2 are d=(-17+sqrt(89))/(10),d=(-17-sqrt(89))/(10)

Find the zeros of 4d^2+17d+10=-d^2

The zeros of 4d^2+17d+10=-d^2 are d=(-17+sqrt(89))/(10),d=(-17-sqrt(89))/(10)

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4 d^{2} + 17 d + 10 = - d^{2}

d = \frac{- 17 + 89}{10}, d = \frac{- 17 - 89}{10}

Decimal Notation

d = - 0.75660 \dots, d = - 2.64339 \dots

Solution steps

4 d^{2} + 17 d + 10 = - d^{2}

Move

d^{2}

to the left side

5 d^{2} + 17 d + 10 = 0

Solve with the quadratic formula

d_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 \cdot 5 \cdot 10}{2 \cdot 5}

1 7^{2} - 4 \cdot 5 \cdot 10 = 89

d_{1, 2} = \frac{- 17 \pm 89}{2 \cdot 5}

Separate the solutions

d_{1} = \frac{- 17 + 89}{2 \cdot 5}, d_{2} = \frac{- 17 - 89}{2 \cdot 5}

d = \frac{- 17 + 89}{2 \cdot 5} : \frac{- 17 + 89}{10}

d = \frac{- 17 - 89}{2 \cdot 5} : \frac{- 17 - 89}{10}

The solutions to the quadratic equation are:

d = \frac{- 17 + 89}{10}, d = \frac{- 17 - 89}{10}

15 - x^{2} = - 14

2 x^{2} - 26 x = - 3 x^{2} - 7 x - 18

(6 x - 3) (- x + 3) = 0

0 = 4 + 23.5 t - 4.9 t^{2}

3 y^{2} - 4 y = 2 y + 7 y

What are the solutions to the equation 4d^2+17d+10=-d^2 ?
The solutions to the equation 4d^2+17d+10=-d^2 are d=(-17+sqrt(89))/(10),d=(-17-sqrt(89))/(10)
Find the zeros of 4d^2+17d+10=-d^2
The zeros of 4d^2+17d+10=-d^2 are d=(-17+sqrt(89))/(10),d=(-17-sqrt(89))/(10)