What are the solutions to the equation 2x^2+20-7x=-2x ?

The solutions to the equation 2x^2+20-7x=-2x are x= 5/4+i(3sqrt(15))/4 ,x= 5/4-i(3sqrt(15))/4

Find the zeros of 2x^2+20-7x=-2x

The zeros of 2x^2+20-7x=-2x are x= 5/4+i(3sqrt(15))/4 ,x= 5/4-i(3sqrt(15))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} + 20 - 7 x = - 2 x

x = \frac{5}{4} + i \frac{3 15}{4}, x = \frac{5}{4} - i \frac{3 15}{4}

Solution steps

2 x^{2} + 20 - 7 x = - 2 x

Move

2 x

to the left side

2 x^{2} + 20 - 5 x = 0

Write in the standard form

a x^{2} + b x + c = 0

2 x^{2} - 5 x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 2 \cdot 20}{2 \cdot 2}

Simplify

(- 5)^{2} - 4 \cdot 2 \cdot 20 : 315 i

x_{1, 2} = \frac{- ( - 5 ) \pm 3 15 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 3 15 i}{2 \cdot 2}, x_{2} = \frac{- ( - 5 ) - 3 15 i}{2 \cdot 2}

x = \frac{- ( - 5 ) + 3 15 i}{2 \cdot 2} : \frac{5}{4} + i \frac{3 15}{4}

x = \frac{- ( - 5 ) - 3 15 i}{2 \cdot 2} : \frac{5}{4} - i \frac{3 15}{4}

The solutions to the quadratic equation are:

x = \frac{5}{4} + i \frac{3 15}{4}, x = \frac{5}{4} - i \frac{3 15}{4}

x^{2} + 4 x - 1

x^{2} + 4 x + 9

x^{2} + 4 x + 6

n, s = \frac{n ( n + 1 )}{2}

4 x^{2} + 45 = - 20 x

What are the solutions to the equation 2x^2+20-7x=-2x ?
The solutions to the equation 2x^2+20-7x=-2x are x= 5/4+i(3sqrt(15))/4 ,x= 5/4-i(3sqrt(15))/4
Find the zeros of 2x^2+20-7x=-2x
The zeros of 2x^2+20-7x=-2x are x= 5/4+i(3sqrt(15))/4 ,x= 5/4-i(3sqrt(15))/4