What are the solutions to the equation x^2+12x+18=0 ?

The solutions to the equation x^2+12x+18=0 are x=3(sqrt(2)-2),x=-3(2+sqrt(2))

Find the zeros of x^2+12x+18=0

The zeros of x^2+12x+18=0 are x=3(sqrt(2)-2),x=-3(2+sqrt(2))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 12 x + 18 = 0

x = 3 (2 - 2), x = - 3 (2 + 2)

Decimal Notation

x = - 1.75735 \dots, x = - 10.24264 \dots

Solution steps

x^{2} + 12 x + 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot 18}{2 \cdot 1}

1 2^{2} - 4 \cdot 1 \cdot 18 = 62

x_{1, 2} = \frac{- 12 \pm 6 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 12 + 6 2}{2 \cdot 1}, x_{2} = \frac{- 12 - 6 2}{2 \cdot 1}

x = \frac{- 12 + 6 2}{2 \cdot 1} : 3 (2 - 2)

x = \frac{- 12 - 6 2}{2 \cdot 1} : - 3 (2 + 2)

The solutions to the quadratic equation are:

x = 3 (2 - 2), x = - 3 (2 + 2)

4 x^{2} - 8 x = 0

20!

4 n^{2} + 12 n + 8

- 5 - (- 3)

∣ x + 3 ∣ \leq 9

What are the solutions to the equation x^2+12x+18=0 ?
The solutions to the equation x^2+12x+18=0 are x=3(sqrt(2)-2),x=-3(2+sqrt(2))
Find the zeros of x^2+12x+18=0
The zeros of x^2+12x+18=0 are x=3(sqrt(2)-2),x=-3(2+sqrt(2))