What are the solutions to the equation 15x^2-29x+8=-4 ?

The solutions to the equation 15x^2-29x+8=-4 are x= 4/3 ,x= 3/5

Find the zeros of 15x^2-29x+8=-4

The zeros of 15x^2-29x+8=-4 are x= 4/3 ,x= 3/5

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15 x^{2} - 29 x + 8 = - 4

x = \frac{4}{3}, x = \frac{3}{5}

Decimal Notation

x = 1.33333 \dots, x = 0.6

Solution steps

15 x^{2} - 29 x + 8 = - 4

Move

4

to the left side

15 x^{2} - 29 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 29 ) \pm ( - 29 ) ^{2} - 4 \cdot 15 \cdot 12}{2 \cdot 15}

(- 29)^{2} - 4 \cdot 15 \cdot 12 = 11

x_{1, 2} = \frac{- ( - 29 ) \pm 11}{2 \cdot 15}

Separate the solutions

x_{1} = \frac{- ( - 29 ) + 11}{2 \cdot 15}, x_{2} = \frac{- ( - 29 ) - 11}{2 \cdot 15}

x = \frac{- ( - 29 ) + 11}{2 \cdot 15} : \frac{4}{3}

x = \frac{- ( - 29 ) - 11}{2 \cdot 15} : \frac{3}{5}

The solutions to the quadratic equation are:

x = \frac{4}{3}, x = \frac{3}{5}

1.25 x^{2} = 15 x

12 x^{2} - 312 x + 1512 = 0

x, 4 x^{2} + 6 y^{2} - z^{2} = - 5

(x + 5) (x + 8) = 180

4 x^{2} - 2.90827 x + 0.528679 = 0

What are the solutions to the equation 15x^2-29x+8=-4 ?
The solutions to the equation 15x^2-29x+8=-4 are x= 4/3 ,x= 3/5
Find the zeros of 15x^2-29x+8=-4
The zeros of 15x^2-29x+8=-4 are x= 4/3 ,x= 3/5