What are the solutions to the equation -16t^2+80t+50=0 ?

The solutions to the equation -16t^2+80t+50=0 are t=-(5(sqrt(6)-2))/4 ,t=(5(2+sqrt(6)))/4

Find the zeros of -16t^2+80t+50=0

The zeros of -16t^2+80t+50=0 are t=-(5(sqrt(6)-2))/4 ,t=(5(2+sqrt(6)))/4

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- 16 t^{2} + 80 t + 50 = 0

t = - \frac{5 ( 6 - 2 )}{4}, t = \frac{5 ( 2 + 6 )}{4}

Decimal Notation

t = - 0.56186 \dots, t = 5.56186 \dots

Solution steps

- 16 t^{2} + 80 t + 50 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 80 \pm 8 0 ^{2} - 4 ( - 16 ) \cdot 50}{2 ( - 16 )}

8 0^{2} - 4 (- 16) \cdot 50 = 406

t_{1, 2} = \frac{- 80 \pm 40 6}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 80 + 40 6}{2 ( - 16 )}, t_{2} = \frac{- 80 - 40 6}{2 ( - 16 )}

t = \frac{- 80 + 40 6}{2 ( - 16 )} : - \frac{5 ( 6 - 2 )}{4}

t = \frac{- 80 - 40 6}{2 ( - 16 )} : \frac{5 ( 2 + 6 )}{4}

The solutions to the quadratic equation are:

t = - \frac{5 ( 6 - 2 )}{4}, t = \frac{5 ( 2 + 6 )}{4}

x^{2} - x - 12 = 0

2 b^{2} + 4 b - 126 = 0

z^{2} + 0.2 z - 0.08 = 0

x^{2} = x + 30

- 3 x^{2} + 15 = 0

What are the solutions to the equation -16t^2+80t+50=0 ?
The solutions to the equation -16t^2+80t+50=0 are t=-(5(sqrt(6)-2))/4 ,t=(5(2+sqrt(6)))/4
Find the zeros of -16t^2+80t+50=0
The zeros of -16t^2+80t+50=0 are t=-(5(sqrt(6)-2))/4 ,t=(5(2+sqrt(6)))/4