What are the solutions to the equation 72+6x=x^2 ?

The solutions to the equation 72+6x=x^2 are x=12,x=-6

Find the zeros of 72+6x=x^2

The zeros of 72+6x=x^2 are x=12,x=-6

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72 + 6 x = x^{2}

x = 12, x = - 6

Solution steps

72 + 6 x = x^{2}

Switch sides

x^{2} = 72 + 6 x

Move

6 x

to the left side

x^{2} - 6 x = 72

Move

72

to the left side

x^{2} - 6 x - 72 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot ( - 72 )}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot (- 72) = 18

x_{1, 2} = \frac{- ( - 6 ) \pm 18}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 18}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 18}{2 \cdot 1}

x = \frac{- ( - 6 ) + 18}{2 \cdot 1} : 12

x = \frac{- ( - 6 ) - 18}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

x = 12, x = - 6

y^{2} + 8 y + 20 = 0

(x - 2)^{2} - 20 = - 45

2 x^{2} - 7 x - 7 = 0

(x + 8) (x - 9) = 0

x^{2} + 4 x + 20 = 10

What are the solutions to the equation 72+6x=x^2 ?
The solutions to the equation 72+6x=x^2 are x=12,x=-6
Find the zeros of 72+6x=x^2
The zeros of 72+6x=x^2 are x=12,x=-6