What are the solutions to the equation 2x^2-7x-7=0 ?

The solutions to the equation 2x^2-7x-7=0 are x=(7+sqrt(105))/4 ,x=(7-sqrt(105))/4

Find the zeros of 2x^2-7x-7=0

The zeros of 2x^2-7x-7=0 are x=(7+sqrt(105))/4 ,x=(7-sqrt(105))/4

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2 x^{2} - 7 x - 7 = 0

x = \frac{7 + 105}{4}, x = \frac{7 - 105}{4}

Decimal Notation

x = 4.31173 \dots, x = - 0.81173 \dots

Solution steps

2 x^{2} - 7 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 2 ( - 7 )}{2 \cdot 2}

(- 7)^{2} - 4 \cdot 2 (- 7) = 105

x_{1, 2} = \frac{- ( - 7 ) \pm 105}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 105}{2 \cdot 2}, x_{2} = \frac{- ( - 7 ) - 105}{2 \cdot 2}

x = \frac{- ( - 7 ) + 105}{2 \cdot 2} : \frac{7 + 105}{4}

x = \frac{- ( - 7 ) - 105}{2 \cdot 2} : \frac{7 - 105}{4}

The solutions to the quadratic equation are:

x = \frac{7 + 105}{4}, x = \frac{7 - 105}{4}

(x + 8) (x - 9) = 0

x^{2} + 4 x + 20 = 10

x^{2} - x - 3

\frac{2 x ^{2}}{5} = 90

6 x^{2} + 31 x + 18 = 0

What are the solutions to the equation 2x^2-7x-7=0 ?
The solutions to the equation 2x^2-7x-7=0 are x=(7+sqrt(105))/4 ,x=(7-sqrt(105))/4
Find the zeros of 2x^2-7x-7=0
The zeros of 2x^2-7x-7=0 are x=(7+sqrt(105))/4 ,x=(7-sqrt(105))/4