What are the solutions to the equation x^2-x+18=-8x+8 ?

The solutions to the equation x^2-x+18=-8x+8 are x=-2,x=-5

Find the zeros of x^2-x+18=-8x+8

The zeros of x^2-x+18=-8x+8 are x=-2,x=-5

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x^{2} - x + 18 = - 8 x + 8

x = - 2, x = - 5

Solution steps

x^{2} - x + 18 = - 8 x + 8

Move

8

to the left side

x^{2} - x + 10 = - 8 x

Move

8 x

to the left side

x^{2} + 7 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot 10 = 3

x_{1, 2} = \frac{- 7 \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 7 + 3}{2 \cdot 1}, x_{2} = \frac{- 7 - 3}{2 \cdot 1}

x = \frac{- 7 + 3}{2 \cdot 1} : - 2

x = \frac{- 7 - 3}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = - 2, x = - 5

x^{2} - 13 x + 1 = - 9 x + 6

Q (Q + 3) = 5 Q + 3

x^{2} + 6 x + 5 = 0

2 x^{2} + 8 x + 2

5 x^{2} = - 15 x - 13

What are the solutions to the equation x^2-x+18=-8x+8 ?
The solutions to the equation x^2-x+18=-8x+8 are x=-2,x=-5
Find the zeros of x^2-x+18=-8x+8
The zeros of x^2-x+18=-8x+8 are x=-2,x=-5