What are the solutions to the equation 2x^2-9x=x^2 ?

The solutions to the equation 2x^2-9x=x^2 are x=9,x=0

Find the zeros of 2x^2-9x=x^2

The zeros of 2x^2-9x=x^2 are x=9,x=0

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2 x^{2} - 9 x = x^{2}

x = 9, x = 0

Solution steps

2 x^{2} - 9 x = x^{2}

Move

x^{2}

to the left side

x^{2} - 9 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot 0 = 9

x_{1, 2} = \frac{- ( - 9 ) \pm 9}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 9}{2 \cdot 1}, x_{2} = \frac{- ( - 9 ) - 9}{2 \cdot 1}

x = \frac{- ( - 9 ) + 9}{2 \cdot 1} : 9

x = \frac{- ( - 9 ) - 9}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

x = 9, x = 0

x^{2} + 3 x + 13 = 0

2 q^{2} + 6 q - 7 = 0

x, f = x^{2} f + g

2 (4 x + 3)^{2} - 46 = - 12

y, x^{2} - 2 x y + 3 y^{2} = 4

What are the solutions to the equation 2x^2-9x=x^2 ?
The solutions to the equation 2x^2-9x=x^2 are x=9,x=0
Find the zeros of 2x^2-9x=x^2
The zeros of 2x^2-9x=x^2 are x=9,x=0