What are the solutions to the equation x^2=22+10x ?

The solutions to the equation x^2=22+10x are x=5+sqrt(47),x=5-sqrt(47)

Find the zeros of x^2=22+10x

The zeros of x^2=22+10x are x=5+sqrt(47),x=5-sqrt(47)

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x^{2} = 22 + 10 x

x = 5 + 47, x = 5 - 47

Decimal Notation

x = 11.85565 \dots, x = - 1.85565 \dots

Solution steps

x^{2} = 22 + 10 x

Move

10 x

to the left side

x^{2} - 10 x = 22

Move

22

to the left side

x^{2} - 10 x - 22 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot ( - 22 )}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot (- 22) = 247

x_{1, 2} = \frac{- ( - 10 ) \pm 2 47}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 2 47}{2 \cdot 1}, x_{2} = \frac{- ( - 10 ) - 2 47}{2 \cdot 1}

x = \frac{- ( - 10 ) + 2 47}{2 \cdot 1} : 5 + 47

x = \frac{- ( - 10 ) - 2 47}{2 \cdot 1} : 5 - 47

The solutions to the quadratic equation are:

x = 5 + 47, x = 5 - 47

2 \cdot 2 x^{\frac{5}{4}} - 2 x^{\frac{1}{4}}

x^{2} - 6 x + 8 \geq 0

\frac{5 ( - 4 ( 4 ) ^{4} + 75 ( 4 ) ^{2} )}{25 - ( 4 ) ^{2}}

13 x^{2} - 16 x = x^{2} - x

What are the solutions to the equation x^2=22+10x ?
The solutions to the equation x^2=22+10x are x=5+sqrt(47),x=5-sqrt(47)
Find the zeros of x^2=22+10x
The zeros of x^2=22+10x are x=5+sqrt(47),x=5-sqrt(47)