What are the solutions to the equation 3(x+7)^2-2=22 ?

The solutions to the equation 3(x+7)^2-2=22 are x=2sqrt(2)-7,x=-2sqrt(2)-7

Find the zeros of 3(x+7)^2-2=22

The zeros of 3(x+7)^2-2=22 are x=2sqrt(2)-7,x=-2sqrt(2)-7

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3 (x + 7)^{2} - 2 = 22

x = 22 - 7, x = - 22 - 7

Decimal Notation

x = - 4.17157 \dots, x = - 9.82842 \dots

Solution steps

3 (x + 7)^{2} - 2 = 22

Move

2

to the right side

3 (x + 7)^{2} = 24

Divide both sides by

3

(x + 7)^{2} = 8

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 7 = 8 : x = 22 - 7

Solve

x + 7 = - 8 : x = - 22 - 7

The solutions to the quadratic equation are:

x = 22 - 7, x = - 22 - 7

x = 13 a^{2}

27 - 4 x + x^{2}

8 x^{2} + 12 = 3 x^{2} + 27

y, x^{2} + x y + 2 y^{2} = 28

x^{2} - 3 x + 2 = 30

What are the solutions to the equation 3(x+7)^2-2=22 ?
The solutions to the equation 3(x+7)^2-2=22 are x=2sqrt(2)-7,x=-2sqrt(2)-7
Find the zeros of 3(x+7)^2-2=22
The zeros of 3(x+7)^2-2=22 are x=2sqrt(2)-7,x=-2sqrt(2)-7