What are the solutions to the equation 130x^2-36x-45=0 ?

The solutions to the equation 130x^2-36x-45=0 are x=(3(6+7sqrt(14)))/(130),x=(3(6-7sqrt(14)))/(130)

Find the zeros of 130x^2-36x-45=0

The zeros of 130x^2-36x-45=0 are x=(3(6+7sqrt(14)))/(130),x=(3(6-7sqrt(14)))/(130)

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130 x^{2} - 36 x - 45 = 0

x = \frac{3 ( 6 + 7 14 )}{130}, x = \frac{3 ( 6 - 7 14 )}{130}

Decimal Notation

x = 0.74288 \dots, x = - 0.46596 \dots

Solution steps

130 x^{2} - 36 x - 45 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 36 ) \pm ( - 36 ) ^{2} - 4 \cdot 130 ( - 45 )}{2 \cdot 130}

(- 36)^{2} - 4 \cdot 130 (- 45) = 4214

x_{1, 2} = \frac{- ( - 36 ) \pm 42 14}{2 \cdot 130}

Separate the solutions

x_{1} = \frac{- ( - 36 ) + 42 14}{2 \cdot 130}, x_{2} = \frac{- ( - 36 ) - 42 14}{2 \cdot 130}

x = \frac{- ( - 36 ) + 42 14}{2 \cdot 130} : \frac{3 ( 6 + 7 14 )}{130}

x = \frac{- ( - 36 ) - 42 14}{2 \cdot 130} : \frac{3 ( 6 - 7 14 )}{130}

The solutions to the quadratic equation are:

x = \frac{3 ( 6 + 7 14 )}{130}, x = \frac{3 ( 6 - 7 14 )}{130}

x^{2} + x - 30 = 0

x^{2} - 24 x + 114 = 19

(3 x + 6)^{2} - 43 = - 34

2 0^{2} = x^{2} + (x - 4)^{2}

2 x^{2} - 13 x - 7 = 9 x

What are the solutions to the equation 130x^2-36x-45=0 ?
The solutions to the equation 130x^2-36x-45=0 are x=(3(6+7sqrt(14)))/(130),x=(3(6-7sqrt(14)))/(130)
Find the zeros of 130x^2-36x-45=0
The zeros of 130x^2-36x-45=0 are x=(3(6+7sqrt(14)))/(130),x=(3(6-7sqrt(14)))/(130)