What are the solutions to the equation -3x^2+11=95 ?

The solutions to the equation -3x^2+11=95 are x=2sqrt(7)i,x=-2sqrt(7)i

Find the zeros of -3x^2+11=95

The zeros of -3x^2+11=95 are x=2sqrt(7)i,x=-2sqrt(7)i

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- 3 x^{2} + 11 = 95

x = 27 i, x = - 27 i

Solution steps

- 3 x^{2} + 11 = 95

Move

11

to the right side

- 3 x^{2} = 84

Divide both sides by

- 3

x^{2} = - 28

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 28, x = - - 28

- 28 = 27 i

- - 28 = - 27 i

x = 27 i, x = - 27 i

x^{2} + 31 = - 12 x

2 x^{2} + 16 x + 26

x, 2 x^{2} - 7 x + 3 = 0

4 x^{2} + 268 = - 72 x

x^{2} + 7 x + 10 = 0

What are the solutions to the equation -3x^2+11=95 ?
The solutions to the equation -3x^2+11=95 are x=2sqrt(7)i,x=-2sqrt(7)i
Find the zeros of -3x^2+11=95
The zeros of -3x^2+11=95 are x=2sqrt(7)i,x=-2sqrt(7)i