What are the solutions to the equation 15(x-1)^2+10=1 ?

The solutions to the equation 15(x-1)^2+10=1 are x=isqrt(3/5)+1,x=-isqrt(3/5)+1

Find the zeros of 15(x-1)^2+10=1

The zeros of 15(x-1)^2+10=1 are x=isqrt(3/5)+1,x=-isqrt(3/5)+1

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15 (x - 1)^{2} + 10 = 1

x = i \frac{3}{5} + 1, x = - i \frac{3}{5} + 1

Solution steps

15 (x - 1)^{2} + 10 = 1

Move

10

to the right side

15 (x - 1)^{2} = - 9

Divide both sides by

15

(x - 1)^{2} = - \frac{3}{5}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 1 = - \frac{3}{5} : x = i \frac{3}{5} + 1

Solve

x - 1 = - - \frac{3}{5} : x = - i \frac{3}{5} + 1

The solutions to the quadratic equation are:

x = i \frac{3}{5} + 1, x = - i \frac{3}{5} + 1

4 x^{2} - 28 x = - 29

x \times x + x = 240

4 (8 + 5 x^{2}) = 352

y, y^{2} = 4 x^{2}

4 x^{2} - 4 x + 26 = 0

What are the solutions to the equation 15(x-1)^2+10=1 ?
The solutions to the equation 15(x-1)^2+10=1 are x=isqrt(3/5)+1,x=-isqrt(3/5)+1
Find the zeros of 15(x-1)^2+10=1
The zeros of 15(x-1)^2+10=1 are x=isqrt(3/5)+1,x=-isqrt(3/5)+1