What are the solutions to the equation x\times x+x=240 ?

The solutions to the equation x\times x+x=240 are x=15,x=-16

Find the zeros of x\times x+x=240

The zeros of x\times x+x=240 are x=15,x=-16

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x \cdot x + x = 240

x = 15, x = - 16

Solution steps

xx + x = 240

Expand

xx + x : x^{2} + x

x^{2} + x = 240

Move

240

to the left side

x^{2} + x - 240 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 240 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 240) = 31

x_{1, 2} = \frac{- 1 \pm 31}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 31}{2 \cdot 1}, x_{2} = \frac{- 1 - 31}{2 \cdot 1}

x = \frac{- 1 + 31}{2 \cdot 1} : 15

x = \frac{- 1 - 31}{2 \cdot 1} : - 16

The solutions to the quadratic equation are:

x = 15, x = - 16

4 (8 + 5 x^{2}) = 352

y, y^{2} = 4 x^{2}

4 x^{2} - 4 x + 26 = 0

x^{2} + 7 x + 12 = 0

- 1 x^{2} + 6 x + 4 = 0

What are the solutions to the equation x\times x+x=240 ?
The solutions to the equation x\times x+x=240 are x=15,x=-16
Find the zeros of x\times x+x=240
The zeros of x\times x+x=240 are x=15,x=-16