What are the solutions to the equation x^2-4x+200=0 ?

The solutions to the equation x^2-4x+200=0 are x=2+14i,x=2-14i

Find the zeros of x^2-4x+200=0

The zeros of x^2-4x+200=0 are x=2+14i,x=2-14i

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x^{2} - 4 x + 200 = 0

x = 2 + 14 i, x = 2 - 14 i

Solution steps

x^{2} - 4 x + 200 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 200}{2 \cdot 1}

Simplify

(- 4)^{2} - 4 \cdot 1 \cdot 200 : 28 i

x_{1, 2} = \frac{- ( - 4 ) \pm 28 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 28 i}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 28 i}{2 \cdot 1}

x = \frac{- ( - 4 ) + 28 i}{2 \cdot 1} : 2 + 14 i

x = \frac{- ( - 4 ) - 28 i}{2 \cdot 1} : 2 - 14 i

The solutions to the quadratic equation are:

x = 2 + 14 i, x = 2 - 14 i

2 (3 x^{2} - 1) = 6 x + 5 x

x^{2} + 12 x = 4

(2 x + 5) (x - 2) = 34

4 x^{2} + 24 = 9

45 n^{2} + 10 n = 0

What are the solutions to the equation x^2-4x+200=0 ?
The solutions to the equation x^2-4x+200=0 are x=2+14i,x=2-14i
Find the zeros of x^2-4x+200=0
The zeros of x^2-4x+200=0 are x=2+14i,x=2-14i