What are the solutions to the equation factor 2(3x^2-1)=6x+5x ?

The solutions to the equation factor 2(3x^2-1)=6x+5x are x=2,x=-1/6

Find the zeros of factor 2(3x^2-1)=6x+5x

The zeros of factor 2(3x^2-1)=6x+5x are x=2,x=-1/6

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2 (3 x^{2} - 1) = 6 x + 5 x

x = 2, x = - \frac{1}{6}

Decimal Notation

x = 2, x = - 0.16666 \dots

Solution steps

2 (3 x^{2} - 1) = 6 x + 5 x

Subtract

6 x + 5 x

from both sides

2 (3 x^{2} - 1) - (6 x + 5 x) = 6 x + 5 x - (6 x + 5 x)

Simplify

2 (3 x^{2} - 1) - 11 x = 0

Factor

2 (3 x^{2} - 1) - 11 x : (x - 2) (6 x + 1)

(x - 2) (6 x + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or 6 x + 1 = 0

Solve

x - 2 = 0 : x = 2

Solve

6 x + 1 = 0 : x = - \frac{1}{6}

The solutions to the quadratic equation are:

x = 2, x = - \frac{1}{6}

x^{2} + 12 x = 4

(2 x + 5) (x - 2) = 34

4 x^{2} + 24 = 9

45 n^{2} + 10 n = 0

4 x^{2} = 25

What are the solutions to the equation factor 2(3x^2-1)=6x+5x ?
The solutions to the equation factor 2(3x^2-1)=6x+5x are x=2,x=-1/6
Find the zeros of factor 2(3x^2-1)=6x+5x
The zeros of factor 2(3x^2-1)=6x+5x are x=2,x=-1/6