What are the solutions to the equation factor 4x^2=25 ?

The solutions to the equation factor 4x^2=25 are x=-5/2 ,x= 5/2

Find the zeros of factor 4x^2=25

The zeros of factor 4x^2=25 are x=-5/2 ,x= 5/2

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4 x^{2} = 25

x = - \frac{5}{2}, x = \frac{5}{2}

Decimal Notation

x = - 2.5, x = 2.5

Solution steps

4 x^{2} = 25

Move

25

to the left side

4 x^{2} - 25 = 0

Factor

4 x^{2} - 25 : (2 x + 5) (2 x - 5)

(2 x + 5) (2 x - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x + 5 = 0 or 2 x - 5 = 0

Solve

2 x + 5 = 0 : x = - \frac{5}{2}

Solve

2 x - 5 = 0 : x = \frac{5}{2}

The solutions to the quadratic equation are:

x = - \frac{5}{2}, x = \frac{5}{2}

3 x^{2} = - 4 x + 15

x^{2} - 6 x - 8 = - 1

x^{2} + 68 = - 18 x

2 x^{2} - 7 x + 5 = 10

5 r^{2} - 7 r + 4 = 6

What are the solutions to the equation factor 4x^2=25 ?
The solutions to the equation factor 4x^2=25 are x=-5/2 ,x= 5/2
Find the zeros of factor 4x^2=25
The zeros of factor 4x^2=25 are x=-5/2 ,x= 5/2