What are the solutions to the equation roots x^2+4x+29 ?

The solutions to the equation roots x^2+4x+29 are x=-2+5i,x=-2-5i

Find the zeros of roots x^2+4x+29

The zeros of roots x^2+4x+29 are x=-2+5i,x=-2-5i

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roots

x^{2} + 4 x + 29

x = - 2 + 5 i, x = - 2 - 5 i

Solution steps

x^{2} + 4 x + 29

The roots are the intercepts with the x-axis

(y = 0)

x^{2} + 4 x + 29 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 29}{2 \cdot 1}

Simplify

4^{2} - 4 \cdot 1 \cdot 29 : 10 i

x_{1, 2} = \frac{- 4 \pm 10 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 10 i}{2 \cdot 1}, x_{2} = \frac{- 4 - 10 i}{2 \cdot 1}

x = \frac{- 4 + 10 i}{2 \cdot 1} : - 2 + 5 i

x = \frac{- 4 - 10 i}{2 \cdot 1} : - 2 - 5 i

The solutions to the quadratic equation are:

x = - 2 + 5 i, x = - 2 - 5 i

5 (m + n - 1) x^{2} + 4 (m - n) x + \frac{mn}{12} = 0

x^{2} - 7 x - 144 = 0

9 w^{2} - 27 w + 20 = 0

16 x^{2} - 25 x = - 9

- x^{2} + 2 x = 2

What are the solutions to the equation roots x^2+4x+29 ?
The solutions to the equation roots x^2+4x+29 are x=-2+5i,x=-2-5i
Find the zeros of roots x^2+4x+29
The zeros of roots x^2+4x+29 are x=-2+5i,x=-2-5i