What are the solutions to the equation factor 2x^2+3x-20=0 ?

The solutions to the equation factor 2x^2+3x-20=0 are x= 5/2 ,x=-4

Find the zeros of factor 2x^2+3x-20=0

The zeros of factor 2x^2+3x-20=0 are x= 5/2 ,x=-4

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2 x^{2} + 3 x - 20 = 0

x = \frac{5}{2}, x = - 4

Decimal

x = 2.5, x = - 4

Solution steps

2 x^{2} + 3 x - 20 = 0

Factor

2 x^{2} + 3 x - 20 : (2 x - 5) (x + 4)

(2 x - 5) (x + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x - 5 = 0 or x + 4 = 0

Solve

2 x - 5 = 0 : x = \frac{5}{2}

Solve

x + 4 = 0 : x = - 4

The solutions to the quadratic equation are:

x = \frac{5}{2}, x = - 4

x^{2} + \frac{3}{2} x - 3 = 0

2 x^{2} - 9 x + 21 = 0

y, y^{2} - 3 x y + 5 x^{2} y = 13 + x y^{2}

x^{2} + 10 x + 21 = 0

4 z^{2} + 11 z + 3 = - 1

What are the solutions to the equation factor 2x^2+3x-20=0 ?
The solutions to the equation factor 2x^2+3x-20=0 are x= 5/2 ,x=-4
Find the zeros of factor 2x^2+3x-20=0
The zeros of factor 2x^2+3x-20=0 are x= 5/2 ,x=-4