What are the solutions to the equation 2c^2-10c+12=0 ?

The solutions to the equation 2c^2-10c+12=0 are c=3,c=2

Find the zeros of 2c^2-10c+12=0

The zeros of 2c^2-10c+12=0 are c=3,c=2

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2 c^{2} - 10 c + 12 = 0

c = 3, c = 2

Solution steps

2 c^{2} - 10 c + 12 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 2 \cdot 12}{2 \cdot 2}

(- 10)^{2} - 4 \cdot 2 \cdot 12 = 2

c_{1, 2} = \frac{- ( - 10 ) \pm 2}{2 \cdot 2}

Separate the solutions

c_{1} = \frac{- ( - 10 ) + 2}{2 \cdot 2}, c_{2} = \frac{- ( - 10 ) - 2}{2 \cdot 2}

c = \frac{- ( - 10 ) + 2}{2 \cdot 2} : 3

c = \frac{- ( - 10 ) - 2}{2 \cdot 2} : 2

The solutions to the quadratic equation are:

c = 3, c = 2

y^{2} - 10 y + 30 = 0

18 x^{2} - 6 = 8 x

y, x^{2} + x y + y^{2} = 4

3 x^{2} + 2 x + 5 = 2 x + 17

x = x^{2} + 4 x + 2

What are the solutions to the equation 2c^2-10c+12=0 ?
The solutions to the equation 2c^2-10c+12=0 are c=3,c=2
Find the zeros of 2c^2-10c+12=0
The zeros of 2c^2-10c+12=0 are c=3,c=2