What are the solutions to the equation 33b=10-7b^2 ?

The solutions to the equation 33b=10-7b^2 are b=-5,b= 2/7

Find the zeros of 33b=10-7b^2

The zeros of 33b=10-7b^2 are b=-5,b= 2/7

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33 b = 10 - 7 b^{2}

b = - 5, b = \frac{2}{7}

Decimal Notation

b = - 5, b = 0.28571 \dots

Solution steps

33 b = 10 - 7 b^{2}

Switch sides

10 - 7 b^{2} = 33 b

Move

33 b

to the left side

10 - 7 b^{2} - 33 b = 0

Write in the standard form

a x^{2} + b x + c = 0

- 7 b^{2} - 33 b + 10 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- ( - 33 ) \pm ( - 33 ) ^{2} - 4 ( - 7 ) \cdot 10}{2 ( - 7 )}

(- 33)^{2} - 4 (- 7) \cdot 10 = 37

b_{1, 2} = \frac{- ( - 33 ) \pm 37}{2 ( - 7 )}

Separate the solutions

b_{1} = \frac{- ( - 33 ) + 37}{2 ( - 7 )}, b_{2} = \frac{- ( - 33 ) - 37}{2 ( - 7 )}

b = \frac{- ( - 33 ) + 37}{2 ( - 7 )} : - 5

b = \frac{- ( - 33 ) - 37}{2 ( - 7 )} : \frac{2}{7}

The solutions to the quadratic equation are:

b = - 5, b = \frac{2}{7}

12 x^{2} - 288 x + 1260 = 0

v, \frac{m v ^{2}}{r} = q v B

\frac{1}{6} z^{2} + \frac{4}{6} z = 2

x^{2} - 8 x + 16 = 0

x^{2} + 3 x + 3 = - 2 x - 3

What are the solutions to the equation 33b=10-7b^2 ?
The solutions to the equation 33b=10-7b^2 are b=-5,b= 2/7
Find the zeros of 33b=10-7b^2
The zeros of 33b=10-7b^2 are b=-5,b= 2/7