What are the solutions to the equation (x+36)^2-38=251 ?

The solutions to the equation (x+36)^2-38=251 are x=-19,x=-53

Find the zeros of (x+36)^2-38=251

The zeros of (x+36)^2-38=251 are x=-19,x=-53

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x + 36)^{2} - 38 = 251

x = - 19, x = - 53

Solution steps

(x + 36)^{2} - 38 = 251

Move

38

to the right side

(x + 36)^{2} = 289

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 36 = 289 : x = - 19

Solve

x + 36 = - 289 : x = - 53

The solutions to the quadratic equation are:

x = - 19, x = - 53

5 x^{2} + 2 x - 3

r^{2} - r - 14 = 2 r

14 x^{2} - 36 x + 16 = 0

2 x^{2} + 36 x + 34 = 0

x^{2} = x + 90

What are the solutions to the equation (x+36)^2-38=251 ?
The solutions to the equation (x+36)^2-38=251 are x=-19,x=-53
Find the zeros of (x+36)^2-38=251
The zeros of (x+36)^2-38=251 are x=-19,x=-53