What are the solutions to the equation 14x^2-36x+16=0 ?

The solutions to the equation 14x^2-36x+16=0 are x=2,x= 4/7

Find the zeros of 14x^2-36x+16=0

The zeros of 14x^2-36x+16=0 are x=2,x= 4/7

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14 x^{2} - 36 x + 16 = 0

x = 2, x = \frac{4}{7}

Decimal Notation

x = 2, x = 0.57142 \dots

Solution steps

14 x^{2} - 36 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 36 ) \pm ( - 36 ) ^{2} - 4 \cdot 14 \cdot 16}{2 \cdot 14}

(- 36)^{2} - 4 \cdot 14 \cdot 16 = 20

x_{1, 2} = \frac{- ( - 36 ) \pm 20}{2 \cdot 14}

Separate the solutions

x_{1} = \frac{- ( - 36 ) + 20}{2 \cdot 14}, x_{2} = \frac{- ( - 36 ) - 20}{2 \cdot 14}

x = \frac{- ( - 36 ) + 20}{2 \cdot 14} : 2

x = \frac{- ( - 36 ) - 20}{2 \cdot 14} : \frac{4}{7}

The solutions to the quadratic equation are:

x = 2, x = \frac{4}{7}

2 x^{2} + 36 x + 34 = 0

x^{2} = x + 90

- 6 x + 3 x^{2} = 0

x^{2} = x + 30

2 x^{2} - 3 = 95

What are the solutions to the equation 14x^2-36x+16=0 ?
The solutions to the equation 14x^2-36x+16=0 are x=2,x= 4/7
Find the zeros of 14x^2-36x+16=0
The zeros of 14x^2-36x+16=0 are x=2,x= 4/7