What are the solutions to the equation -6x+3x^2=0 ?

The solutions to the equation -6x+3x^2=0 are x=2,x=0

Find the zeros of -6x+3x^2=0

The zeros of -6x+3x^2=0 are x=2,x=0

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- 6 x + 3 x^{2} = 0

x = 2, x = 0

Solution steps

- 6 x + 3 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

3 x^{2} - 6 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 3 \cdot 0}{2 \cdot 3}

(- 6)^{2} - 4 \cdot 3 \cdot 0 = 6

x_{1, 2} = \frac{- ( - 6 ) \pm 6}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 6}{2 \cdot 3}, x_{2} = \frac{- ( - 6 ) - 6}{2 \cdot 3}

x = \frac{- ( - 6 ) + 6}{2 \cdot 3} : 2

x = \frac{- ( - 6 ) - 6}{2 \cdot 3} : 0

The solutions to the quadratic equation are:

x = 2, x = 0

x^{2} = x + 30

2 x^{2} - 3 = 95

2 x^{2} + 4 x - 1 = x + 1

x^{2} + 7 x - \frac{23}{4} = 0

- 5 x^{2} + 5 = 0

What are the solutions to the equation -6x+3x^2=0 ?
The solutions to the equation -6x+3x^2=0 are x=2,x=0
Find the zeros of -6x+3x^2=0
The zeros of -6x+3x^2=0 are x=2,x=0