What are the solutions to the equation 2x^2+4x-1=x+1 ?

The solutions to the equation 2x^2+4x-1=x+1 are x= 1/2 ,x=-2

Find the zeros of 2x^2+4x-1=x+1

The zeros of 2x^2+4x-1=x+1 are x= 1/2 ,x=-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} + 4 x - 1 = x + 1

x = \frac{1}{2}, x = - 2

Decimal Notation

x = 0.5, x = - 2

Solution steps

2 x^{2} + 4 x - 1 = x + 1

Move

1

to the left side

2 x^{2} + 4 x - 2 = x

Move

x

to the left side

2 x^{2} + 3 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 2 ( - 2 )}{2 \cdot 2}

3^{2} - 4 \cdot 2 (- 2) = 5

x_{1, 2} = \frac{- 3 \pm 5}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 3 + 5}{2 \cdot 2}, x_{2} = \frac{- 3 - 5}{2 \cdot 2}

x = \frac{- 3 + 5}{2 \cdot 2} : \frac{1}{2}

x = \frac{- 3 - 5}{2 \cdot 2} : - 2

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - 2

x^{2} + 7 x - \frac{23}{4} = 0

- 5 x^{2} + 5 = 0

y, x^{2} y - 4 x = 5

2 x^{2} + 6 x = - 4

y, x^{2} y^{2} = 3 x

What are the solutions to the equation 2x^2+4x-1=x+1 ?
The solutions to the equation 2x^2+4x-1=x+1 are x= 1/2 ,x=-2
Find the zeros of 2x^2+4x-1=x+1
The zeros of 2x^2+4x-1=x+1 are x= 1/2 ,x=-2